Question

Find the z-score that has 62.8% of the distribution’s area to its left

Answer 1

`\mathbb P(Z<z)=F_Z(z)=0.628\implies z={F_Z}^(-1)(0.628)\approx0.3266`

where
`F_Z(z)` is the cumulative distribution function for the random variable
`Z` following the standard normal distribution.