Question

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A spherical object has a diameter of 18 cm. It has a spherical inner core with a diameter of 9 cm.
What is the volume of the outer layer?
Use 3.14 to approximate pi. Round to the nearest hundredth if necessary.
Enter your answer in the box.

cm³

Answer 1

The answer is 2670.57 (i just took the quiz so this is the answer for sure)

Answer 2

The volume of the outer layer is 2670.57 cm³ .

Explanation:

Formula

`Volume\ of\ a\ sphere = (4)/(3) \pi r^(3)`

Where r is the radius of the sphere .

As given

A spherical object has a diameter of 18 cm.

It has a spherical inner core with a diameter of 9 cm.

Let us assume that the radius of the spherical object is represented by R .

Let us assume that the radius of the inner object is represented by r .

`Diameter (R) = (18)/(2)`

= 9 cm

`Diameter (R) = (9)/(2)`

= 4.5 cm

`\pi = 3.14`

Volume of the outer layer = Volume of the spherical object - Volume of the inner core .

`Volume\ of\ a\ outer\ layer = (4)/(3)* 3.14* 9* 9* 9 - (4)/(3)* 3.14* 4.5* 4.5* 4.5`

`Volume\ of\ a\ outer\ layer = (4* 3.14* 9* 9* 9)/(3)- (4* 3.14* 4.5* 4.5* 4.5)/(3)`

`Volume\ of\ a\ outer\ layer = (9156.24)/(3)- (1144.53)/(3)`

`Volume\ of\ a\ outer\ layer = 3052.08-381.51`

`Volume\ of\ a\ outer\ layer = 2670.57\ cm^(3)`

Therefore the volume of the outer layer is 2670.57 cm³ .