Find the area of a 9-inch by 6-inch rectangle with a 4-inch by 4-inch square removed from one corner. a 70 in.mc001-1.jpg b 38 in.mc001-3.jpg c 200 in.mc001-2.jpg d 46 in.mc001-…

Question

asked Nov 13, 2018 215k views

2 Answers

Nishant Ghodke · Answer 1 · 2018-11-17T17:59:40+0000

Answer: B.
$38\ in^2$

Explanation:

Area of a rectangle with dimension " l by w" is given by :-

Area of square with dimension "a by a" is given by :_

Now Using (1), Area of rectangle with dimension 9-inch by 6-inch will be :-

$A_r=9* 9=54\ in^2$

Using (2), Area of square with dimension 4-inch by 4-inch will be :-

$A_s=4^2=16\ in^2$

Now, the required area =
$A_r-A_s=54-16=38\ in^2$

Hence, B is the correct option.