Question

3. Which of the following operations yields the number of moles of solute? (1 point) molarity × moles of solution molarity × liters of solution molarity × mass of solution moles of solutions ÷ volume of solution 4. To 225 mL of a 0.80M solution of KI, a student adds enough water to make 1.0 L of a more dilute KI solution. What is the molarity of the new solution? (1 point) 180M 2.8M 0.35M 0.18M 5. Which of the following is NOT a colligative property of a solution? (1 point) boiling point elevation supersaturation vapor pressure lowering freezing point depression 6. A solute depresses the freezing point because the solute ____. (1 point) is colder than the solvent disrupts crystal formation of the solvent disrupts crystal formation of the solvent tends to sink to the bottom of the solution has bigger molecules than the solvent 7. How many milliliters of alcohol are in 167 mL of an 85.0% (v/v) alcohol solution? (1 point) 252 mL 228 mL 145 mL 142 mL

Answer 1

3. molarity × liters of solution

Step-by-step explanation:

Answer 2

3. Molarity × solution.
4. You get 225mL in litres, meaning 0.255L. Then multiply that by the 0.8mol/L to get the number of moles which is 0.18. Then you divide that by the litres which is 1. So your answer is 0.18mol/L.