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What mass of water is needed to react with 98.7g of Li3N

asked
User Uros
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7.9k points

1 Answer

4 votes
moles Li3N = 98.7 g/34.8297 g/mol=2.83

the ratio between Li3N and H2O is 1 : 3
moles water neeeded = 2.83 x 3=8.49
mass water = 8.49 mol x 18.02 g/mol=153.0 g

moles NH3 produced = 2.83
molescules of NH3 = 2.83 x 6.02 x 10^23=1.70 x 10^24

moles NH3 (STP) = 45.0/22.4 =2.0
moles Li3N = 2.0
mass Li3N = 2.0 x 34.8297 g/mol=69.6 g
answered
User Manas Sambare
by
8.3k points
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