Question

What is the volume of 425 g of ice, if the density of the ice is 0.92 g/mL

Answer 1

The volume would be 461.96 mL.

This is pretty simple. To solve, just divide the mass by the density and you'll get the volume. Since the volume for this particular equation was a generally long decimal, I would round to the nearest hundredth.

425 / .92
461.96

Hope this helps! :)

Answer 2

The volume of 425 g of ice, if the density of the ice is
`0.92(g)/(mL)` is 461.96 mL=0.46 L

Step-by-step explanation:

The equation to find the volume is:

`V=(m)/(d)` (1)

Where:

V: Volume

m: Mass

d: Density

We know the mass of ice (425 g) and the density (
`0.92(g)/(mL)). With this information we can replace in the eq (1) and we will find the volume</p><p>[tex]V=(m)/(d)`

`V=(425 g)/(0.92(g)/(mL))`

`V=461.96 mL`

If we want to know the volume in liters, we know 1L=1000mL

`V=461.96 mL*(1 L)/(1000mL)`

`V=0.46 L`

The volume is 461.96 mL or 0.46 L