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What is the logarithmic form of the equation e2x ≈ 1732?

What is the logarithmic form of the equation e2x ≈ 1732?
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What is the logarithmic form of the equation e2x ≈ 1732?

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User PandemoniumSyndicate
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2 Answers

1 vote

Answer:

ln 1732 = 2x

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User Wafeeq
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e2x ≈ 1732, lne2x ≈ ln 1732 and 2xlne= ln 1732, but lne=1, finally x=(1/2) ln1732
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User Tliokos
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