Question

The class average on a math test was 77.5 and the standard deviation was 5.8 find the Z score for a test score of 83 and the percentage of the class who scored below 83

Answer 1

`Z=(83-77.5)/(5.8)\approx0.9483`


`\mathbb P(X<83)=\mathbb P(Z<0.9483)\approx0.8285=82.85\%`