1 mole of phosphoric acid (H3PO4) and 1.75 moles of NaOH are added to the one liter water. Calculate the pH.

Question

asked Oct 1, 2018 3.9k views

1 Answer

Cpalmer · Answer 1 · 2018-10-07T11:45:14+0000

Moles of H⁺ released by each mole of acid = 3
Moles of H⁺ released = 3

Moles of OH⁻ released = 1.75

Moles of H⁺ remaining = 3 - 1.75 = 1.25 mol/dm³

pH = -log[H⁺]
pH = -log(1.25)
pH = -0.1

1 mole of phosphoric acid (H3PO4) and 1.75 moles of NaOH are added to the one liter water. Calculate the pH.

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Related questions

Categories

Other Questions