Question

When a quantity of monatomic ideal gas expands at a constant pressure of 4.00×104pa, the volume of the gas increases from 2.00×10−3m3 to 8.00×10−3m3?

Answer 1

This can be verified if we know the values of the initial (T1) and final (T2) temperatures. We use the ideal gas equation for this: PV=RT.

P1V1=RT1
(40000 Pa)*(0.002 m^3) = (8.314 m3Pa/molK)(T1)
T1 = 9.62 K


P2V2=RT2
(40000 Pa)*(0.008 m^3) = (8.314 m3Pa/molK)(T2)
T2 = 33.5 K

Thus, this is true if the monoatomic ideal gas is heated from 9.62 K to 33.5 K at constant pressure.

Answer 2

Yes that is correct. We know this because 4.00 x 10 4 Pa is constant. If you have 2.00×10−3m3 then you do the following: (2.00×10^−3)(4.00×10^ 4) = 8.00×10^−3. That is how you get your answer