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Wнaт'ѕ тнe eхpreѕѕιon υѕιng eхponenтѕ м.м.м.p.p.p.p.p.p

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User Mwoa
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3 votes
(m*m*m)*(p*p*p*p*p*p) is (m^1*m^1*m^1)*(p^1*p^1*p^1*p^1*p^1*p^1) so what I'm trying to say is m equals 1+1+1 and p equals 1+1+1+1+1+1.
answered
User JamesHalsall
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3 votes

\bf m\cdot m\cdot m\cdot m\cdot p\cdot p\cdot p\cdot p\cdot p\cdot p \\ \quad \\ m^1\cdot m^1\cdot m^1\cdot m^1\cdot p^1\cdot p^1\cdot p^1\cdot p^1\cdot p^1\cdot p^1 \\ \quad \\ m^(1+1+1)p^(1+1+1+1+1+1)\implies m^{\boxed{?}}p^{\boxed{?}}
answered
User Fernando Aspiazu
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8.4k points

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