asked 214k views
2 votes
If a 50 N force pulls on a 10 kg object,how much acceleration will occur?

asked
User MosheK
by
8.2k points

2 Answers

3 votes
Assuming that the force of friction does not equal to the force at which you are pulling at, hence Fnet is not zero, to solve for acceleration need to use the following equation:

Fnet = ma
a = Fnet/m
a = 50 N/10 kg
a = 5 N/kg or a = 5 m/s^2.
answered
User Pshirishreddy
by
8.7k points
4 votes

Answer:

The value of acceleration occurred is
5 m/s^2.

Step-by-step explanation:

Force is a push or pull on an object with mass which causes in change in its velocity Or it is the product of its mass and acceleration by which that object is moving.

Force =
mass* acceleration

F = ma

We have:

F = 50 N, a = ? , m = 10 kg

Putting in the values we get,


50 N=10 kg* a


a=(50 N)/(10 kg)=5 m/s^2

The value of acceleration occurred is
5 m/s^2.

answered
User Eyalm
by
7.6k points

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