Question

A roller coaster starts down a hill at 10 m/s. Three seconds later, its speed is 32 m/s. What is the roller coaster’s acceleration?

-7.3 m/s2

7.3 m/s

-7.3 m/s

7.3 m/s 2

Answer 1

Final velocity(v) = 32 m/s
Initial velocity(u) = 10 m/s

Using kinematic equation v = u + at,

32 = 10 + a(3)

32-10
--------- = a
3

a = 22
----
3

a = 7.3 m/s^2.

Hence acceleration of the roller coaster is 7.3 m/s^2.

Hope this helps!!