Question

The perimeter of a parallelogram EFGH is 48 in. If EF is 5 in les than EH, find the lengths of all four sides

Answer 1

Let the lengths of EH and FG = x
Let the lengths of EF and HG = x-5
Solve,
X + X + (X-5) + (X-5) = 48
4X - 10 = 48
4X = 58
X = 14.5
EH= 14.5
FG = 14.5
EF = 9.5
HG = 9.5