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Normal distributed mean of 200pounds and a standard deviation of 20 pounds what percent would be over 250 pounds

Normal distributed mean of 200pounds and a standard deviation of 20 pounds what percent would be over 250 pounds
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normal distributed mean of 200pounds and a standard deviation of 20 pounds what percent would be over 250 pounds

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User Jaydeep Rajput
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\mathbb P(X>250)=\mathbb P\left((X-200)/(20)>(250-200)/(20)\right)=\mathbb P(Z>2.5)\approx0.0062=0.62\%
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User Tal Darom
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