Question

In a reaction where A + B AB, what does an equilibrium position of A= 14%, B = 14%, and AB= 72% indicate about the reaction?

Answer 1

A.) Because A and B are equal, the reaction has reached equilibrium.
B.) There is more A and B than AB at equilibrium, and the reaction favors the reactants.
C.) There is more AB than A and B at equilibrium, and the reaction favors the products.
D.) There is more AB than A and B at equilibrium, and the reaction favors the reactants.
E.) The reaction is not at equilibrium.
These are the answer choices pls help

Answer 2

The answer is c I just answered mine .