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Formula: 4NH3+5O2 -> 4NO + 6H2O. In an experiment, 3.25 grams of NH3 are allowed to react with 3.5 grams of O2. How many moles of NO will be produced from this reaction? How many grams of NO will be produced from this reaction? How many grams of NO will be produced from this reaction?

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User Banjara
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Formula: 4NH3+5O2 -> 4NO + 6H2O. In an experiment, 3.25 grams of NH3 are allowed-example-1
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User Nathua
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