Which expression below gives the average rate of change of the function h(x)= (1)/(2) (3 ^(x+1/2)) + 3 on the interval 0 < x < 3?

Question

Which expression below gives the average rate of change of the function


`h(x)= (1)/(2) (3 ^(x+1/2)) + 3` on the interval 0 < x < 3?

Answer 1

I know
just use the slope
just do
(h(3)-h(0))/(3-0)

so
h(3)=
`(27/2) √(3) +3`
h(0)=
`(1/2) √(3) +3`

the average slope is
`(13√(3))/(3)`