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Solving simultaneous equations with a quadratic, y=2x+5 and y=x^2-x-5

Solving simultaneous equations with a quadratic, y=2x+5 and y=x^2-x-5
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Solving simultaneous equations with a quadratic, y=2x+5 and y=x^2-x-5

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User Yoani
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8.1k points

1 Answer

1 vote
Set equal to eachother:
2x+5=x^2-x-5
0=x^2 - 3x -10
0=(x-5)(x+2)
x = -2, 5
answered
User Masjum
by
8.5k points
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