Question

2x+4\x^2+4x+3 divided by x^2-4/x+1

Answer 1

remember
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)

so
first factor them

`( (2(x+2))/((x+1)(x+3)) )( ((x-2)(x+2))/(x+1) )`=

`( (2(x+2))/((x+1)(x+3)) )( (x+1)/((x-2)(x+2)) )`=

`(2(x+2)(x+1))/((x+1)(x+3)(x-2)(x+2))`=
factor out ones

`( (2)/((x+3)(x-2)) )( ((x+2)(x+1))/((x+2)(x+1)) )`=

`( (2)/((x+3)(x-2)) )(1)`=

`(2)/((x+3)(x-2))`=

`(2)/(x^2+x-6)`