Question

A home is to be built on a 61 foot 6 inches wide lot. the house is 7 feet 2 inches from the side of the lot and is 41 foot 6 inches wide

Answer 1

x= unknown distance

7'2" + 41'6" + x = 61'6"

48'8"+x=61'6"

x=61'6"-48'8"

x=60'18"-48'8"

x = 12'10" 12 ft. 10 in.

Therefore the distance of the house from the other side of the lot is 12 ft 10 inches.

Hope this helps!