Question

John has 8 less nickels than dimes. If there is $8.30 in the purse, which equation could be used to determine the number of each type of coin?

Answer 1

So we know that John has 8 less nickels than dimes.

10¢= one dime

5¢= on nickel

8x5=40

Multiply 8 with 5 first because you know John hase 8 less nickels than dimes.

Subtract $8.30 with 40¢. Answer: $7.90. $7.90 divide 10 is 79 so then the left over is 0.

Final result: 79 dimes and 8 nickels.