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What is the value of r in the equation 2(2r + 8) = 3r + 16?

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2(2r + 8) = 3r + 16
4r + 16 = 3r +16
4r - 3r = 16 - 16
r = 0
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User Eduardo Macedo
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Answer:

The value of r is 0

Explanation:

Given the equation 2(2r + 8) = 3r + 16

We have to find the value of r

2(2r + 8) = 3r + 16

By distributive property,

a(b+c)=ab+ac

⇒ 2(2r)+2(8)=3r+16

⇒ 4r+16=3r+16

⇒ 4r-3r=16-16

r=0

hence, the value of r is 0.

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User Sebastian Scholl
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