How many grams of water are needed to react with 485 g of calcium carbide

Question

asked May 8, 2018 92.0k views

1 Answer

Yuval Perelman · Answer 1 · 2018-05-13T14:17:46+0000

The procedure for this is the next one:
moles CaC2 = 485 g/64.1 g/mol=7.57
moles H2O = 2 x 7.57 =15.1
mass H2O = 15.1 mol x 18.02 g/mol=272.8 g