Question

T object]user: solve y2 4y – 32 = 0 using the zero product property

Answer 1

The zero product property means that 0a=0.


(I'm assuming that by y2 you mean y squared btw)



`y^(2) 4y - 32 = 0`



`4y - 32 = (0)/( y^(2) )`


the zero divided by y is zero:



`4y - 32 = 0`


move the 4y



`-32 = 4y`


`(-32)/(4) = y`



`y = -8`

Hope that helps!