A plane rises from take-off and flies at an angle of 8° with the horizontal runway. When it has gained 850 feet, find the distance to the nearest foot, the plane has flown. 850 …

Question

asked Dec 18, 2022 9.2k views

1 Answer

Noh · Answer 1 · 2022-12-22T20:56:30+0000

Answer:

$C\approx 5748.2feet$

Explanation:

From the question we are told that

Angle of elevation
$\thata=8 \textdegree$

Height of plane
H=850feet

Generally the equation for the Distance flown is given by

$C=(H)/(sin \theta)$

C=(800)/(sin8)

C=5748.237227

$C\approx 5748.2feet$

Therefore Distance flown is

$C\approx 5748.2feet$