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Which number is the remainder for (7x3 + 4x2 – 9x + 37) divided by (x – 5)?

Which number is the remainder for (7x3 + 4x2 – 9x + 37) divided by (x – 5)?
asked 169k views
22 votes
Which number is the remainder for (7x3 + 4x2 – 9x + 37) divided by (x – 5)?

asked
User Kanke
by
8.0k points

1 Answer

10 votes

Answer:

Solving it would turn into these:

(20x+37)/ x- 5

20+ (137/x-5)

answered
User Manojlds
by
8.3k points
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