Question

How many grams of IRON are

contained in a 245 gram sample

of Fe2O3?

Answer 1

`m_(Fe)=171.7gFe`

Step-by-step explanation:

Hello!

In this case, since we have 245 of iron (III) oxide, we first need to compute the moles contained there:

`n_(Fe_2O_3)=245gFe_2O_3*(1molFe_2O_3)/(159.7gFe_2O_3) =1.54molFe_2O_3`

Now, as 1 mole of iron (III) oxide is related to 2 moles of iron, due to iron's subscript in the molecule, we get the moles of iron itself:

`n_(Fe)=1.54molFe_2O_3*(2molFe)/(1molFe_2O_3) =3.08molFe`

And the mass is computed based on the atomic mass of iron:

`m_(Fe)=3.08molFe*(55.8gFe)/(1molFe) \\\\m_(Fe)=171.7gFe`

Best regards!