Question

You throw a rock off the top of a building with an initial velocity of 10.0 m/s. It takes 12.0 s to hit the ground. How tall is the building? Help

Answer 1

t=12s
u=10m/s
acceleration due to gravity=9.8m/s^2

s=ut+1/2at^2
s=10(12)+1/2(9.8)(12)^2
s=825.6m