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5 votes
25x^2+40x+16=28




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1 Answer

3 votes
Solution:
1. Move all terms to one side
25{x}^{2}+40x+16-28=0 2. Simplify 25{x}^{2}+40x+16-28 to 25x​2​​+40x−12
25{x}^{2}+40x-12=0 3. Apply the Quadratic Formulax=\frac{-40+20\sqrt{7}}{50},\frac{-40-20\sqrt{7}}{50}

4. Simplify solutions
x=-\frac{2(2-\sqrt{7})}{5},-\frac{2(2+\sqrt{7})}{5} Done!
answered
User Igor Dymov
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