Question

A certain lightning bolt moves 50.0 c of charge. how many fundamental units of charge (qe) is this?

Answer 1

Answer: There are
`3.125\tims 10^(20)` number of electrons.

Step-by-step explanation:

We are given 50 Coulombs of charge and we need to find the number of electrons that can hold this much amount of charge. So, to calculate that we will use the equation:

`nq_e=Q`

where,

n = number of electrons

`q_e` Charge of one electron =
`1.6* 10^(-19)C`

Q = Total charge = 50 C.

Putting values in above equation, we get:

`n* 1.6* 10^(-19)C=50C\\\\n=(50C)/(1.6* 10^(-19)C)\\\\n=3.125* 10^(20)C`

Hence, there are
`3.125\tims 10^(20)` number of electrons.

Answer 2

The lightning bolt that moves 50.0 C of charge is converted to qe units. The conversion factor is 1 coulumb is equivalent to 6.24150975·10^18 e. Thus, converting 50 C to e is:

50.0 C * (6.24150975x10^18 e)/1C
equals 3.120754875x10^20 e