Question

A. Write the equation for the line labeled Line 1.

B. Write the equation for the line labeled Line 2.
C. Write the equation of a line that would be parallel to Line 2.
D. Write the equation of a line that would be perpendicular to Line 2.

Answer 1

Line 1 is a horizontal line so the equation of the line for line 1 is Y = 8 Line 2, first solve the slope of the line using points ( -4 , -5) and ( 0, -2) M = (y1 – y2) / (x1 – x2) M = ( -5 – ( -2)) / ( -4 – 0) M = ¾ Since its y intercept is at ( 0,-2) B = -2 Y = ¾ x -2 For c and d you should give a point at which the line is perpendicular or parallel

Answer 2

a)

The line labelled l1 is a horizontal line.

The equation of the horizontal line is y = b, where b is the point where it intersects the y axis.

Line l1 intersects the y axis at (0,8).

The equation of line l1 is y = 8.

b)

Line l2 passes through (4,1) and (0,-2)

m=Slope of line =
`(-2-1)/(0-4)= (-3)/(-4)= (3)/(4)`

Also -2 is the y intercept.

So b = -2

The equation is

y=mx+b

y=
`(3)/(4)x-2`

3)

Any line parallel to the given line has the same slope but different y intercept.

So y =
`(3)/(4)x+2`

shall be the equation of a line parallel to line l2

d)

For a perpendicular line its slope is -1/m

Slope =
`-(1)/( (3)/(4) )=-(4)/(3)`

Let the y intercept be 1

The equation of line shall be

`y=- (4)/(3)x+1`