What are the real root of the given power equation! 3(x-4)4/3 +16=64

Question

asked Jan 28, 2018 40.8k views

1 Answer

Speednet · Answer 1 · 2018-02-03T16:16:14+0000

3(x-4 ) \frac{4}{3} + 16= 64

The 3's cancel out so the new equation becomes 4(x-4) + 16 = 64

Expand the brackets
4x -16 + 16 = 64
4x=64
x= 16