Question

What is the electric field experienced by a charged balloon if the charge on the balloon is 9.4 × 10-10 coulombs and the force it experiences is 8.2 × 10-2 newtons?

Answer 1

We know, F = q.E
E = F/q
Here, F = 8.2 * 10⁻²
q = 9.4 * 10⁻¹⁰

Substitute values into the expression:
E = 8.2 * 10⁻² / 9.4 * 10⁻¹⁰
E = 8.72 * 10⁷ N/C

Hope this helps!

Answer 2

Electric field,
`E=8.72* 10^7\ N/C`

Step-by-step explanation:

It is given that,

Charge on the balloon,
`q=9.4* 10^(-10)\ C`

Force experienced by the balloon,
`F=8.2* 10^(-2)\ N`

The relation between electric force and electric field is given by :

`E=(F)/(q)`

`E=(8.2* 10^(-2))/(9.4* 10^(-10))`

`E=8.72* 10^7\ N/C`

Hence, the electric field experienced by a charged balloon is
`8.72* 10^7\ N/C`