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Which of the following statements is/are true? (5 points)

I.If f '(x) exists and is nonzero for all x, then f(1) ≠ f(0)
II.If f is differentiable for all x and f (-1) = f(1), then there is a number c, such that |c| < 1 and f '(c) = 0.
III.If f '(c) = 0, then f has a local maximum or minimum at x = c.



I only
II only
I and III only
I and II only

2 Answers

1 vote

Final answer:

The statements about derivatives given to the student involve understanding the Mean Value Theorem and the conditions for a function to have a local extremum. Only statements II (related to the Mean Value Theorem) and III (concerning potential local extrema) are true. Statement I is false because a constant nonzero derivative can still yield equal function values at different points.

Step-by-step explanation:

The student's question involves calculus, specifically about the properties of differentiable functions and their derivatives. To answer each of the given statements:

Statement I: If f '(x) exists and is nonzero for all x, this does not automatically imply that f(1) ≠ f(0). This statement is false because f(x) could still be a linear function with a constant non-zero slope. In such a case, f '(x) would indeed be nonzero for all x, but f(1) could be equal to f(0) plus the slope.

Statement II: This is a restatement of the Mean Value Theorem (MVT) and is true. If f is differentiable between -1 and 1 and continuous on the closed interval [-1, 1], and f(-1) = f(1), then by MVT there must be some c in (-1, 1) such that f '(c) = 0.

Statement III: The fact that f '(c) = 0 implies only that c could be a point where f has a local maximum, a local minimum, or neither (it could be a point of inflection). So, this statement is true, as it says 'or' not 'and'.

The correct answer to the question is II and III only.

answered
User Grumme
by
8.2k points
1 vote

Answer:

the answer would be I and II only

Step-by-step explanation:

answered
User VladCovaliov
by
7.9k points
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