Register

What is x+9=2(x_1)^2 in the form of ax^2+bx +c=0

What is x+9=2(x_1)^2 in the form of ax^2+bx +c=0
asked 35.2k views
2 votes
What is x+9=2(x_1)^2 in the form of ax^2+bx +c=0

asked
User Mschmidt
by
7.8k points

1 Answer

3 votes
x + 9 = 2(x - 1)^2
x + 9 = 2(x^2 - 2x + 1)
x + 9 = 2x^2 - 4x + 2
2x^2 - 4x + 2 - x - 9 = 0
2x^2 - 5x -7 =0
answered
User Mike Gardner
by
7.8k points
← Prev Question Next Question →

Related questions

User Om
asked Jun 20, 2024 228k views
Exponential function is a function of the form: a. y = a(1+r)^t b. Ax + By = C c. y = mx + b d. y-y_1 = m(x – x_1)
Om asked Jun 20, 2024
by Om
6.9k points
1 answer
3 votes
228k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
How do you estimate of 4 5/8 X 1/3
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Link Copied!