Find two consecutive even integers whose product is

Question

asked Dec 17, 2018 117k views

1 Answer

Pushparaj · Answer 1 · 2018-12-23T05:17:23+0000

You can't find the precise integer without knowing what the product is - your question is incomplete - but you can find a general solution.

If

is one of the integers, then the next even integer is given by
x+2

. So if the product is

, then you have

$x(x+2)=k\implies x^2+2x=k\implies x^2+2x+1=k+1\implies (x+1)^2=k+1\implies x=-1\pm√(k+1)$

Plug in

and select the solution for

that is an even integer.