What's the ratio in the compound iron(II) sulfide?

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asked Jul 3, 2018 232k views

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Safakeskin · Answer 1 · 2018-07-09T03:56:24+0000

To determine the ratio of atoms present in this ionic compound, first write the charges of the ions, and swap the charges to determine the subscripts of the atoms.

Fe^+2 S^-2
FeS.

This refers to the ratio as 1 Fe ion for 1 S ion.

What's the ratio in the compound iron(II) sulfide?

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