Reaction: 2HCl + Zn → ZnCl₂ + H₂
Now, Molar mass of Zn = Given mass / Molecular mass
Molar mass = 5.25 / 65.38 [ Molar mass of Zn = 65.38 g/mol ]
Molar mass = 0.0802 mol
Now, As reaction requires twice as many moles of HCl as it does Zn, we will need = 0.0802 × 2 = 0.1605 moles of HCl
We know, Volume = moles / molarity
Here, moles = 0.1605 mol
molarity = 3.50 M
Substitute their values in the formula,
Volume = 0.1605 / 3.50
V = 0.04588 L
V = 45.88 mL
So, final answer of your question would be 45.88 mL
Hope this helps!