Question

x^2-6x=-1 If the quadratic equation has real solutions, what are the solutions? Explain. Estimate irrational solutions to the nearest tenth.

Answer 1

x^2 -6x +1 = 0
a=1
b = -6
c = 1

Use the quadratic formula
x = [-b +- sq root (b^2 -4ac)] / 2a
x = [--6 +- sq root (36 - 4)] / 2
x = [ 6 +- sq root (32)] / 2
sq root (32) = 5.657

x1 = [ 6 + 5.657] / 2
x1 = 11.657 / 2
x1 = 5.8285
x1 = 5.82 (to nearest tenth)

x2 = [ 6 - 5.657] / 2
x2 = .343 / 2
x2 = .1715
x2 = .2 (to nearest tenth)