Question

Consider 2NH3(g)+3CuO(s)→N2(g)+3Cu(s)+3H2O(g) 2NH 3 ​ (g)+3CuO(s)→N 2 ​ (g)+3Cu(s)+3H 2 ​ O(g). What volume (in mL) of NH3 NH 3 ​ is required to completely react 45.2 g of CuO at STP? Enter your solution as a numerical value with no units.

Answer 1

the volume of in Ml of NH3 required to completely react with 45.2 g of CUO at STP is 8489.6 Ml

calculation
calculate the moles of CUO used
moles= mass/molar mass
45.2 g/79.5 g/mol =0.569 moles

Reacting equation
2NH3 + 3CUO = N2 +3CU +3H2O
by use of reacting ratio between NH3 to CUO which jis 2:3 the moles of NH3 = 0.569 x2/3 = 0.379 moles

At STP 1 mole = 22.4 L
what about 0.379 moles

=0.379 x22.4 = 8.4896 L

in Ml = 8.4896 x1000 =8489.6 ml