Question

If f(x)=x-6 and g(x)=x^1/2(x+3) what is f(x) times g(x)

Answer 1

(x²-3x-18)√x, or (x-6)(x+3)√x

Explanation:

Answer 2

`f(x)=x-6;\ g(x)=x^(1)/(2)(x+3)\\\\f(x)\cdot g(x)=(x-6)\cdot x^(1)/(2)(x+3)=x^(1)/(2)(x-6)(x+3)=x^(1)/(2)(x^2+3x-6x-18)\\\\=x^(1)/(2)(x^2-3x-18)=(x^2-3x-18)√(x)`