If a quantity you calculated has units of (kgm^2)/(s^2c), what is that quantity?

Question

asked Jan 27, 2019 140k views

1 Answer

Jimijazz · Answer 1 · 2019-01-31T04:47:03+0000

The units of the quantity are:

([kg] [m]^2)/([s]^2 [C])

We can isolate one
([m])/([s]^2)

, which corresponds to an acceleration, a:

= ([kg][m] a)/([C]) =

[kg] corresponds to a mass, m; [m] corresponds to a length, L; C corresponds to a charge, Q:

= (maL)/(Q)

But the product ma is a force, F:

= (FL)/(Q)

and the product FL is a work, so an energy, U:

= (U)/(Q)

and this ratio corresponds to an electrical potential. So, the quantity is an electrical potential.