Question

Whats the distance from point y to qx in the figure

Answer 1

Because the triangle XYZ is a right triangle, you can use the pythagorean theorm which is a^2 + b^2 = c^2
the c^2 is always the hypotenuse and the a and b don't matter
10^2 + b^2 = (10 rad 2)^2
100 + b^2 = (10 rad 2)(10 rad 2)
100 + b^2 = 100 * 2 --> rad 2 times rad 2 = 2 (the radical cancels out)
100 + b^2 = 200
100-100 + b^2 = 200-100
b^2 = 100
b = rad 100
b = 10
the distance from point Y to WX is 10 (answer is B)

Answer 2

The distance from point
`y` to
`WX` is just the measure of the line segment
`YZ`. Notice that
`YZ` is one of the sides of the right triangle
`XYZ`, so to find its length we are going to use the Pythagorean theorem:

`(YZ)^2=(XY)^2-(XZ)^2`

`(YZ)^2=(10 √(2) )^2-10^2`

`(YZ)^2=200-100`

`(YZ)^2=100`

`YZ= √(100)`

`YZ=10`

We can conclude that the correct answer is B. 10