Question

Jamal simplified ...

Answer 1

`\bf √(75x^5y^8)\qquad \begin{cases} 75=3\cdot 25\\ \qquad 3\cdot 5^2\\ x^5=x^(4+1)\\ \qquad x^4x^1\\ \qquad (x^2)^2x\\ y^8=y^(4\cdot 2)\\ \qquad (y^4)^2 \end{cases}\implies √(3\cdot 5^2\cdot (x^2)^2x(y^4)^2) \\\\\\ 5x^2y^4√(3x)`