Question

Solve by the quadratic formula: m^2 -6m+4=0

Can you please show the steps.

Answer 1

The quadratic formula is:


`x= (-b \pm √(b^2-4ac) )/(2a)`

In your equation:

`a=1`

`b=-6`

`c=4`

So now we just plug and chug:


`x= (-(-6) \pm √((-6)^2-4(1)(4)) )/(2(1))`


`x= (6 \pm √(36-16) )/(2)`


`x= (6 \pm √(20) )/(2)`


`x= (6 \pm 2√(5) )/(2)`


`x= 3\pm √(5) }`

So the two solutions are
`x= 3 + √(5) }` and
`x= 3 - √(5) }`