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{14x}^(4) {y}^(7) / {6x}^(5) {y}^(4)

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\frac{ {14x}^(4) {y}^(7) }{ {6x}^(5) {y}^(4) } = \frac{ {7y}^(3) }{3x} = 3 \frac{ {y}^(3) }{3x}

Hope this helps. - M
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User Scott Robinson
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