Question

The equilibrium concentrations were found to be [br2] = 2.2 × 10−3 m, [cl2] = 3.0 × 10−2 m, and [brcl] = 1.5 × 10−2 m. write the equilibrium expression, and calculate the equilibrium constant for this reaction at this temperature.

Answer 1

`Br_(2) + Cl_(2)---\ \textgreater \ 2BrCl K_(eq) = ([BrCl]^(2))/([Br_(2)][Cl_(2)]]) = ([1.5*10^(-2)]^(2))/([2.2*10^(-3)][3.0*10^(-2)]) =0.34*10=3.4 K_(eq)=3.4`