ABCD is an isosceles trapezoid with legs AB and CD, and base BC. If the length of AB = 6y +5, the length of BC= 4y - 6, and the length of CD= 2y +1, what is the value of y?

Question

asked Feb 8, 2019 108k views

1 Answer

Matt Westlake · Answer 1 · 2019-02-12T02:01:05+0000

ABCD is an isosceles trapezoid with legs AB and CD
∴ AB = CD

AB = 6y +5

CD= 2y +1

∴ 6y + 5 = 2y + 1
6y - 2y = 5 - 1
4y = 4

∴ y = 4/4 = 1