asked 107k views
5 votes
A hyperbola centered at the origin has a vertex at (9, 0) and a focus at (−15, 0).

Which are the equations of the asymptotes?

asked
User PJvG
by
7.5k points

2 Answers

4 votes

Answer:

C

Explanation:

answered
User Ggirodda
by
8.0k points
4 votes
Hyperbola equation opening horizontally:

(x^2)/(a^2) - (y^2)/(b^2) = 1
Asymptotes:

y = \pm (b)/(a) x

'a' is distance vertex is from center --> a = 9
'c' is distance focus is from center --> c = 15

a^2 + b^2 = c^2 \\ \\ b^2 = 15^2 - 9^2 = 144 \\ \\ b = 12

Asymptotes are:

y = \pm (12)/(9) x = \pm (4)/(3) x
answered
User Eduardomoroni
by
7.7k points
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